What is the tangent of y=(4x)/(x^2+1),(1,2) ?

The tangent of y=(4x)/(x^2+1),(1,2) is y=2

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tangent of y=(4x)/(x^2+1),(1,2)

tangent of

y = \frac{4 x}{x ^{2} + 1}, (1, 2)

y = 2

Solution steps

Find the slope of

y = \frac{4 x}{x ^{2} + 1} : \frac{d y}{d x} = \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x ^{2} + 1}

(1, 2) : m = 0

Find the line with slope m=

0

and passing through

(1, 2) : y = 2

y = 2

\int 2 + t d t

x \to \infty lim (x^{- 2} e^{2 x})

\frac{d}{d x} (e^{(2 x)^{3} - 2})

What is the tangent of y=(4x)/(x^2+1),(1,2) ?
The tangent of y=(4x)/(x^2+1),(1,2) is y=2