What is laplacetransform-t/4-3/8 sin(2t) ?

The answer to laplacetransform-t/4-3/8 sin(2t) is -1/(4s^2)-3/(4(s^2+4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform-t/4-3/8 sin(2t)

laplace transform

- \frac{t}{4} - \frac{3}{8} sin (2 t)

- \frac{1}{4 s ^{2}} - \frac{3}{4 ( s ^{2} + 4 )}

Solution steps

L {- \frac{t}{4} - \frac{3}{8} sin (2 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= - \frac{1}{4} L {t} - \frac{3}{8} L {sin (2 t)}

L {t} : \frac{1}{s ^{2}}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= - \frac{1}{4} \cdot \frac{1}{s ^{2}} - \frac{3}{8} \cdot \frac{2}{s ^{2} + 4}

Refine

- \frac{1}{4} \frac{1}{s ^{2}} - \frac{3}{8} \frac{2}{s ^{2} + 4} : - \frac{1}{4 s ^{2}} - \frac{3}{4 ( s ^{2} + 4 )}

= - \frac{1}{4 s ^{2}} - \frac{3}{4 ( s ^{2} + 4 )}

\int_{0}^{1} π (x - x^{4}) d x

\int - 3 x^{- 1} d x

f (x) = (x^{3} - 2)

(2 x - 7)^{5}

\int sin (5 x) cos (6 x) d x

What is laplacetransform-t/4-3/8 sin(2t) ?
The answer to laplacetransform-t/4-3/8 sin(2t) is -1/(4s^2)-3/(4(s^2+4))