What is the sum from n=0 to infinity of (-1)^n(-2)^n ?

The sum from n=0 to infinity of (-1)^n(-2)^n is diverges

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sum from n=0 to infinity of (-1)^n(-2)^n

n = 0 \sum \infty (- 1)^{n} (- 2)^{n}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} (- 2)^{n}

(- 2)^{n} = 2^{n} (- 1)^{n}

= n = 0 \sum \infty (- 1)^{n} \cdot 2^{n} (- 1)^{n}

Simplify

(- 1)^{n} \cdot 2^{n} (- 1)^{n} : 2^{n}

= n = 0 \sum \infty 2^{n}

Apply Series Geometric Test:

diverges

= diverges

\frac{2 s + 1}{( s + 1 ) ^{2}}

x \to - 2 lim (2 x^{2} - 8 x - 3)

\int \frac{9 x ^{2} - 8 x + 16}{x ^{3} + 4 x} d x

\int e^{c o s (11 t)} sin (11 t) d t

\frac{d}{d x} (\frac{1}{9})

What is the sum from n=0 to infinity of (-1)^n(-2)^n ?
The sum from n=0 to infinity of (-1)^n(-2)^n is diverges