What is the solution for y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1 ?

The solution for y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1 is y=e^t

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y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y = e^{t}

Solution steps

y^{''} (t) + 2 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = e^{t}

y = e^{t}

y = x e^{3 x}

\int 1 + t^{3} d t

n = 0 \sum \infty (- 1)^{n} (- 2)^{n}

\frac{2 s + 1}{( s + 1 ) ^{2}}

x \to - 2 lim (2 x^{2} - 8 x - 3)

What is the solution for y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1 ?
The solution for y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1 is y=e^t