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Popular >

y^'=e^{x+y}

Solution

y^{^{'}} = e^{x + y}

Solution

y = - ln (- e^{x} - c_{1})

Solution steps

y^{'} (x) = e^{x + y}

Solve separable ODE:

y = - ln (- e^{x} - c_{1})

y = - ln (- e^{x} - c_{1})

Popular Examples

y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=1

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 1

derivative of y=xe^{3x}derivative of

y = x e^{3 x}

integral of sqrt(1+t^3)

\int 1 + t^{3} d t

sum from n=0 to infinity of (-1)^n(-2)^n

n = 0 \sum \infty (- 1)^{n} (- 2)^{n}

inverse oflaplace (2s+1)/((s+1)^2)inverse laplace

\frac{2 s + 1}{( s + 1 ) ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{x+y} ?
The solution for y^'=e^{x+y} is y=-ln(-e^x-c_{1})