What is area y=-x^2-2x,y=-2x-4,x=-3,x=0 ?

The answer to area y=-x^2-2x,y=-2x-4,x=-3,x=0 is 23/3

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area y=-x^2-2x,y=-2x-4,x=-3,x=0

area

y = - x^{2} - 2 x, y = - 2 x - 4, x = - 3, x = 0

\frac{23}{3}

Decimal Notation

7.66666 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{0} x^{2} - 4 d x

Solve

\int_{- 3}^{0} x^{2} - 4 d x : \frac{23}{3}

The area is:

= \frac{23}{3}

y^{^{'''}} + y^{^{'}} = tan (x)

\frac{d}{d x} (6 sec (x) - 5 x)

x \to - 1 lim ((x + 3 x^{3})^{4})

y^{^{'}} = e^{x + y}

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 1

What is area y=-x^2-2x,y=-2x-4,x=-3,x=0 ?
The answer to area y=-x^2-2x,y=-2x-4,x=-3,x=0 is 23/3