What is the f(x)=cos(x^{ln(x^2+1)}) ?

The f(x)=cos(x^{ln(x^2+1)}) is Domain: x>0 Intercepts: None Asymptotes: None

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f(x)=cos(x^{ln(x^2+1)})

f (x) = cos (x^{l n (x^{2} + 1)})

Domain : x > 0

Intercepts : None

Asymptotes : None

Interval Notation

Domain : (0, \infty)

Solution steps

Domain of

cos (x^{l n (x^{2} + 1)}) : x > 0

Axis interception points of

cos (x^{l n (x^{2} + 1)}) :

None

Asymptotes of

cos (x^{l n (x^{2} + 1)}) :

None

n = 0 \sum \infty \frac{n !}{3 ^{n}}

\int 103 t^{2} d t

\frac{d}{d x} (9 x + \frac{1}{x} - 4)

x \to 3 lim (4 - x)

y = \frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )}

What is the f(x)=cos(x^{ln(x^2+1)}) ?
The f(x)=cos(x^{ln(x^2+1)}) is Domain: x>0<br/>Intercepts: None<br/>Asymptotes: None