en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+3y=5

Solution

y^{^{'}} + 3 y = 5

Solution

y = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{5}{3}

Solution steps

y^{'} (t) + 3 y = 5

Solve separable ODE:

y = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{5}{3}

y = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{5}{3}

Popular Examples

limit as x approaches infinity of (x^3+2x+4)/(e^{1x)+1}

x \to \infty lim (\frac{x ^{3} + 2 x + 4}{e ^{1 x} + 1})

normal of y=4x^2-6x,\at x=2 normal of

y = 4 x^{2} - 6 x, at x = 2

(dy)/(dx)=(y^2+x^2)/(yx)

\frac{d y}{d x} = \frac{y ^{2} + x ^{2}}{y x}

integral of cos^9(x)

\int cos^{9} (x) d x

integral of (8x^3-3x^2+8)

\int (8 x^{3} - 3 x^{2} + 8) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+3y=5 ?
The solution for y^'+3y=5 is y=-(e^{-3t-c_{1}})/3+5/3