What is the ((sqrt(x^2+25))/2+(9-x)/3)^' ?

The ((sqrt(x^2+25))/2+(9-x)/3)^' is x/(2sqrt(x^2+25))-1/3

What is the first ((sqrt(x^2+25))/2+(9-x)/3)^' ?

The first ((sqrt(x^2+25))/2+(9-x)/3)^' is x/(2sqrt(x^2+25))-1/3

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(\frac{x ^{2} + 25}{2} + \frac{9 - x}{3})^{^{'}}

\frac{x}{2 x ^{2} + 25} - \frac{1}{3}

Solution steps

(\frac{x ^{2} + 25}{2} + \frac{9 - x}{3})^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (\frac{x ^{2} + 25}{2})^{^{'}} + (\frac{9 - x}{3})^{^{'}}

(\frac{x ^{2} + 25}{2})^{'} = \frac{x}{2 x ^{2} + 25}

(\frac{9 - x}{3})^{'} = - \frac{1}{3}

= \frac{x}{2 x ^{2} + 25} - \frac{1}{3}

\int x^{7} - 4 x^{- 3} + 1 d x

\int 4 x e^{- x^{2}} d x

y^{^{'}} + y = - 1

\frac{d}{d x} (tan (arccos (x)))

\int_{0}^{1} (x + 1)^{3} d x

What is the ((sqrt(x^2+25))/2+(9-x)/3)^' ?
The ((sqrt(x^2+25))/2+(9-x)/3)^' is x/(2sqrt(x^2+25))-1/3
What is the first ((sqrt(x^2+25))/2+(9-x)/3)^' ?
The first ((sqrt(x^2+25))/2+(9-x)/3)^' is x/(2sqrt(x^2+25))-1/3