What is the derivative of x^2+cos(x) ?

The derivative of x^2+cos(x) is 2x-sin(x)

What is the first derivative of x^2+cos(x) ?

The first derivative of x^2+cos(x) is 2x-sin(x)

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\frac{d}{d x} (x^{2} + cos (x))

2 x - sin (x)

Solution steps

\frac{d}{d x} (x^{2} + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 x - sin (x)

n = 1 \sum \infty \frac{4 ^{n}}{4 ^{n}}

\frac{d}{d x} (4 x^{4} e^{x})

\int - x + tan (x) d x

y = sin (x) - cos (x)

\int \frac{1}{( 1 - x ^{2} )} d x

What is the derivative of x^2+cos(x) ?
The derivative of x^2+cos(x) is 2x-sin(x)
What is the first derivative of x^2+cos(x) ?
The first derivative of x^2+cos(x) is 2x-sin(x)