What is the solution for -y^{'''}-y^{''}+5y^{''}-3=0 ?

The solution for -y^{'''}-y^{''}+5y^{''}-3=0 is y=c_{1}e^{4t}+c_{2}+c_{3}t+(3t^2)/8

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-y^{'''}-y^{''}+5y^{''}-3=0

- y^{^{'''}} - y^{^{''}} + 5 y^{^{''}} - 3 = 0

y = c_{1} e^{4 t} + c_{2} + c_{3} t + \frac{3 t ^{2}}{8}

Solution steps

- y^{'''} (t) - y^{''} (t) + 5 y^{''} (t) - 3 = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} + c_{3} t + \frac{3 t ^{2}}{8}

y = c_{1} e^{4 t} + c_{2} + c_{3} t + \frac{3 t ^{2}}{8}

\frac{\partial}{\partial x} (17 - 4 x^{2} - y^{2})

\frac{\partial}{\partial x} (\frac{y}{cos ( x )})

\frac{d}{d x} (\frac{4}{5} ln ((9 x^{2} - 6)^{7}))

\int_{2}^{4} \frac{( 2 x - 3 )}{6} d x

x \to 2 lim (x^{2} - x)

What is the solution for -y^{'''}-y^{''}+5y^{''}-3=0 ?
The solution for -y^{'''}-y^{''}+5y^{''}-3=0 is y=c_{1}e^{4t}+c_{2}+c_{3}t+(3t^2)/8