What is (\partial)/(\partial y)(z^3-x^2y) ?

The answer to (\partial)/(\partial y)(z^3-x^2y) is -x^2

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(\partial)/(\partial y)(z^3-x^2y)

\frac{\partial}{\partial y} (z^{3} - x^{2} y)

- x^{2}

Solution steps

\frac{\partial}{\partial y} (z^{3} - x^{2} y)

Treat

z, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (z^{3}) - \frac{\partial}{\partial y} (x^{2} y)

\frac{\partial}{\partial y} (z^{3}) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

= 0 - x^{2}

Simplify

= - x^{2}

(x cos (x))^{^{'}}

f (x) = x^{3} (3 - x^{2})

f (x) = \frac{x}{x ^{2} - 7}

\int \frac{2 x}{( x - 3 ) ^{2}} d x

n \to 2 lim (\frac{1}{n ^{2}})

What is (\partial)/(\partial y)(z^3-x^2y) ?
The answer to (\partial)/(\partial y)(z^3-x^2y) is -x^2