What is (\partial)/(\partial x)(x^2+y^2sqrt(y^2+1)) ?

The answer to (\partial)/(\partial x)(x^2+y^2sqrt(y^2+1)) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2+y^2sqrt(y^2+1))

\frac{\partial}{\partial x} (x^{2} + y^{2} y^{2} + 1)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} y^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2} y^{2} + 1)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2} y^{2} + 1) = 0

= 2 x + 0

Simplify

= 2 x

x \to 0 lim (x \cdot \frac{1}{x})

\int e^{- 6 x^{2}} d x

\int (\frac{ln ( x )}{x}) d x

x \to \infty lim (6 x^{4})

y = 2 x (x + 1)^{2}, (0, 0)

What is (\partial)/(\partial x)(x^2+y^2sqrt(y^2+1)) ?
The answer to (\partial)/(\partial x)(x^2+y^2sqrt(y^2+1)) is 2x