What is the integral of (ln(13x))/x ?

The integral of (ln(13x))/x is (ln^2(13x))/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ln(13x))/x

\int \frac{ln ( 13 x )}{x} d x

\frac{ln ^{2} ( 13 x )}{2} + C

Solution steps

\int \frac{ln ( 13 x )}{x} d x

Apply u-substitution

: \int \frac{ln ( u )}{u} d u

= \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{v ^{2}}{2}

Substitute back

= \frac{ln ^{2} ( 13 x )}{2}

Add a constant to the solution

= \frac{ln ^{2} ( 13 x )}{2} + C

e^{3 x}

x \to \infty lim (\frac{e ^{2 x}}{5 ^{2 x}})

\frac{d}{d x} ((x^{2} + 1)^{4})

\int_{1}^{7} x^{3} d x

25 - x^{2}

What is the integral of (ln(13x))/x ?
The integral of (ln(13x))/x is (ln^2(13x))/2+C