What is the derivative of x^4-5x+1 ?

The derivative of x^4-5x+1 is 4x^3-5

What is the first derivative of x^4-5x+1 ?

The first derivative of x^4-5x+1 is 4x^3-5

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\frac{d}{d x} (x^{4} - 5 x + 1)

4 x^{3} - 5

Solution steps

\frac{d}{d x} (x^{4} - 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (1) = 0

= 4 x^{3} - 5 + 0

Simplify

= 4 x^{3} - 5

\int_{0}^{3} 2 π (5 - x) (9 - x^{2}) d x

arcsin (x)

\frac{0.707}{s + 0.707}

\frac{d}{d x} (a \cdot cos (x) + b \cdot sin (x))

\int (2 (z + 1) e^{2 x - 2} + 2 y) d x

What is the derivative of x^4-5x+1 ?
The derivative of x^4-5x+1 is 4x^3-5
What is the first derivative of x^4-5x+1 ?
The first derivative of x^4-5x+1 is 4x^3-5