What is (\partial)/(\partial x)(-4y(-2x-y-3)) ?

The answer to (\partial)/(\partial x)(-4y(-2x-y-3)) is 8y

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(\partial)/(\partial x)(-4y(-2x-y-3))

\frac{\partial}{\partial x} (- 4 y (- 2 x - y - 3))

8 y

Solution steps

\frac{\partial}{\partial x} (- 4 y (- 2 x - y - 3))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 y \frac{\partial}{\partial x} (- 2 x - y - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 4 y (- \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (3))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (3) = 0

= - 4 y (- 2 - 0 - 0)

Simplify

= 8 y

\int 1 - \frac{16}{sin ^{4} ( x )} d x

x \to 0 lim (x ln^{2} (x))

\frac{\partial}{\partial x} (3 y^{2} - x^{2})

\frac{d}{d x} (\frac{x ^{2} + 4}{4 x ^{3} - 5 x})

- 5 e^{- 5 x + 2}

What is (\partial)/(\partial x)(-4y(-2x-y-3)) ?
The answer to (\partial)/(\partial x)(-4y(-2x-y-3)) is 8y