What is the limit as x approaches 1 of 2x^2-4x+2 ?

The limit as x approaches 1 of 2x^2-4x+2 is 0

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limit as x approaches 1 of 2x^2-4x+2

x \to 1 lim (2 x^{2} - 4 x + 2)

0

Solution steps

x \to 1 lim (2 x^{2} - 4 x + 2)

Plug in the value

x = 1

= 2 \cdot 1^{2} - 4 \cdot 1 + 2

Simplify

= 0

\frac{\partial}{\partial y} (\frac{3 y}{x ^{5}})

y^{^{''}} - 3 y^{^{'}} + 4 y = x e^{x}

\frac{d}{d x} (1 (- 5 x + 3) (- 3 x + 2))

\int \frac{( e ^{x} )}{e ^{x} + 1} d x

\frac{\partial}{\partial x} (x^{2} - 2 x y + y^{2})

What is the limit as x approaches 1 of 2x^2-4x+2 ?
The limit as x approaches 1 of 2x^2-4x+2 is 0