What is the solution for (dy)/(dx)=(1+e^{2x}) ?

The solution for (dy)/(dx)=(1+e^{2x}) is y=x+1/2 e^{2x}+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(1+e^{2x})

\frac{d y}{d x} = (1 + e^{2 x})

y = x + \frac{1}{2} e^{2 x} + c_{1}

Solution steps

\frac{d y}{d x} = (1 + e^{2 x})

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = (1 + e^{2 x})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 1 + e^{2 x} d x

\int 1 + e^{2 x} d x = x + \frac{1}{2} e^{2 x} + c_{1}

y = x + \frac{1}{2} e^{2 x} + c_{1}

\frac{d}{d x} (\frac{x ^{2}}{x - 9})

(- 8, 9), (- 2, - 3)

x y + y^{^{'}} = 100 x

\int_{- 3}^{1} 2 x + 2 d x

f (x) = x^{3} - 3 x^{2} + 1

What is the solution for (dy)/(dx)=(1+e^{2x}) ?
The solution for (dy)/(dx)=(1+e^{2x}) is y=x+1/2 e^{2x}+c_{1}