What is the integral of 1/((1+2x^2)) ?

The integral of 1/((1+2x^2)) is 1/(sqrt(2))arctan(sqrt(2)x)+C

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integral of 1/((1+2x^2))

\int \frac{1}{( 1 + 2 x ^{2} )} d x

\frac{1}{2} arctan (2 x) + C

Solution steps

\int \frac{1}{1 + 2 x ^{2}} d x

Apply Integral Substitution

= \int \frac{1}{2 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= \frac{1}{2} arctan (u)

Substitute back

u = 2 x

= \frac{1}{2} arctan (2 x)

Add a constant to the solution

= \frac{1}{2} arctan (2 x) + C

x \to \frac{π}{2} + lim (tan (x))

x y^{^{'}} = x e^{x} - 2 y

x \to - 6 lim (x^{2})

4 + 2 x + 10 x e^{x}

f (x) = (3 - 5 x e^{x}) (3 x + 2)

What is the integral of 1/((1+2x^2)) ?
The integral of 1/((1+2x^2)) is 1/(sqrt(2))arctan(sqrt(2)x)+C