What is the solution for (dy)/(dt)=2y+y^3,y(0)=1 ?

The solution for (dy)/(dt)=2y+y^3,y(0)=1 is y=sqrt((2e^{4t))/(3-e^{4t)}}

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(dy)/(dt)=2y+y^3,y(0)=1

\frac{d y}{d t} = 2 y + y^{3}, y (0) = 1

y = \frac{2 e ^{4 t}}{3 - e ^{4 t}}

Solution steps

\frac{d y}{d t} = 2 y + y^{3}

Solve Bernoulli ODE:

y = \frac{2 e ^{4 t}}{3 - e ^{4 t}}

y = \frac{2 e ^{4 t}}{3 - e ^{4 t}}

x^{\frac{2}{7}}

4 x - 3

y = \frac{4 x}{1 + x ^{2}}, (4, \frac{16}{17})

\int_{0}^{\frac{π}{2}} - 3 sin^{2} (3 x) d x

\frac{( 3 - 2 s )}{( s ^{2} + 4 s + 5 )}

What is the solution for (dy)/(dt)=2y+y^3,y(0)=1 ?
The solution for (dy)/(dt)=2y+y^3,y(0)=1 is y=sqrt((2e^{4t))/(3-e^{4t)}}