What is derivative of f(x)=(2t+1)/(t+3) ?

The answer to derivative of f(x)=(2t+1)/(t+3) is (dt)/(dx)=0

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derivative of f(x)=(2t+1)/(t+3)

derivative of

f (x) = \frac{2 t + 1}{t + 3}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{2 t + 1}{t + 3}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{5 \frac{d t}{d x}}{( t + 3 ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

y = 2 x^{2} + 3, (0, 3)

\int \frac{x ^{2} + 1}{1 - x ^{2}} d x

x \to \frac{5 π}{6} lim (sin (x))

\frac{d y}{d x} = (x y)^{2}, y (0) = 1

\int \frac{x ^{5}}{x ^{6} + 2} d x

What is derivative of f(x)=(2t+1)/(t+3) ?
The answer to derivative of f(x)=(2t+1)/(t+3) is (dt)/(dx)=0