What is the limit as x approaches-1 of (|x+1|)/(x+1) ?

The limit as x approaches-1 of (|x+1|)/(x+1) is diverges

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limit as x approaches-1 of (|x+1|)/(x+1)

x \to - 1 lim (\frac{∣ x + 1 ∣}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{∣ x + 1 ∣}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{∣ x + 1 ∣}{x + 1}) = 1

x \to - 1 - lim (\frac{∣ x + 1 ∣}{x + 1}) = - 1

= diverges

\int_{1}^{2} (2 x + 1) ln (x) d x

\int \frac{x ^{2} + 1}{x ^{3} + 3 x - 16} d x

\int e^{2 t} + e^{- 2 t} + 2 d t

\int x ln (x^{2} + 1) d x

\frac{1}{s ^{2} ( s + 1.1 )}

What is the limit as x approaches-1 of (|x+1|)/(x+1) ?
The limit as x approaches-1 of (|x+1|)/(x+1) is diverges