What is the solution for y^{''}-16y^'+63y=240e^x ?

The solution for y^{''}-16y^'+63y=240e^x is y=c_{1}e^{9x}+c_{2}e^{7x}+5e^x

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y^{''}-16y^'+63y=240e^x

y^{^{''}} - 16 y^{^{'}} + 63 y = 240 e^{x}

y = c_{1} e^{9 x} + c_{2} e^{7 x} + 5 e^{x}

Solution steps

y^{''} (x) - 16 y^{'} (x) + 63 y = 240 e^{x}

Solve linear ODE:

y = c_{1} e^{9 x} + c_{2} e^{7 x} + 5 e^{x}

y = c_{1} e^{9 x} + c_{2} e^{7 x} + 5 e^{x}

\int \frac{x - 5}{x ^{2} + 2 x - 3} d x

f (x) = \frac{3}{5 x + 2}, at x = - 1

y = x, y = x^{3}

\int (2 x + 1)^{\frac{5}{6}} d x

\frac{\partial}{\partial x} (32 x + 13 y + 90)

What is the solution for y^{''}-16y^'+63y=240e^x ?
The solution for y^{''}-16y^'+63y=240e^x is y=c_{1}e^{9x}+c_{2}e^{7x}+5e^x