What is the sum from n=0 to infinity of (3^n)/(5^{2n+1)} ?

The sum from n=0 to infinity of (3^n)/(5^{2n+1)} is converges

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sum from n=0 to infinity of (3^n)/(5^{2n+1)}

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{2 n + 1}}

converges

Solution steps

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{2 n + 1}}

Apply Series Ratio Test:

converges

= converges

x \to 1 lim (x + 3 e x - 1 + 1)

1. 8^{2 x}

\frac{( 2 s + 1 )}{s ^{2} + 2 s + 1}

y^{^{'}} = x^{2}

n = 1 \sum \infty \frac{5}{4 ^{n + 1}}

What is the sum from n=0 to infinity of (3^n)/(5^{2n+1)} ?
The sum from n=0 to infinity of (3^n)/(5^{2n+1)} is converges