What is the integral of 3e^x-2cos(x) ?

The integral of 3e^x-2cos(x) is 3e^x-2sin(x)+C

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integral of 3e^x-2cos(x)

\int 3 e^{x} - 2 cos (x) d x

3 e^{x} - 2 sin (x) + C

Solution steps

\int 3 e^{x} - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 e^{x} d x - \int 2 cos (x) d x

\int 3 e^{x} d x = 3 e^{x}

\int 2 cos (x) d x = 2 sin (x)

= 3 e^{x} - 2 sin (x)

Add a constant to the solution

= 3 e^{x} - 2 sin (x) + C

f (x) = x^{4} + 8 x^{2} - x, at x = 1

\int \frac{5}{x ^{2}} d x

\frac{d}{d x} (1 + \frac{1}{3 x})

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + 5})

11 + tan^{2} (x)

What is the integral of 3e^x-2cos(x) ?
The integral of 3e^x-2cos(x) is 3e^x-2sin(x)+C