What is the sum from n=1 to infinity of 1/(e^{2n)} ?

The sum from n=1 to infinity of 1/(e^{2n)} is converges

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sum from n=1 to infinity of 1/(e^{2n)}

n = 1 \sum \infty \frac{1}{e ^{2 n}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{e ^{2 n}}

Apply Series Ratio Test:

converges

= converges

(12 - 20 y + e^{- 5 x}) d x - 4 d y = 0

\int 8 x^{\frac{1}{3}} + 8 x^{- \frac{1}{3}} d x

\int_{0}^{2} ln (2 x) d x

\frac{\partial}{\partial x} (\frac{y}{ln ( x - 1 )})

\frac{d y}{d t} + a y = 0

What is the sum from n=1 to infinity of 1/(e^{2n)} ?
The sum from n=1 to infinity of 1/(e^{2n)} is converges