What is the tangent of f(x)=x^2-6 ?

The tangent of f(x)=x^2-6 is y=2a_{0}x-a_{0}^2-6

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tangent of f(x)=x^2-6

tangent of

f (x) = x^{2} - 6

y = 2 a_{0} x - a_{0}^{2} - 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 6)

Find the slope of

f (x) = x^{2} - 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 6

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} - 6) : y = 2 a_{0} x - a_{0}^{2} - 6

y = 2 a_{0} x - a_{0}^{2} - 6

\int_{0}^{\infty} 77 \frac{e ^{x}}{e ^{2 x} + 3} d x

y \cdot y^{^{'}} = 1

\int \frac{1}{1 - 4 ^{2}} d x

\int_{- 4}^{4} (16 - x^{2}) d x

y^{^{'}} = \frac{x}{x - 1}, y (2) = 5

What is the tangent of f(x)=x^2-6 ?
The tangent of f(x)=x^2-6 is y=2a_{0}x-a_{0}^2-6