What is the integral of (x^2)/(\sqrt[3]{x+3)} ?

The integral of (x^2)/(\sqrt[3]{x+3)} is 3/8 (x+3)^{8/3}-18/5 (x+3)^{5/3}+27/2 (x+3)^{2/3}+C

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integral of (x^2)/(\sqrt[3]{x+3)}

\frac{3}{8} (x + 3)^{\frac{8}{3}} - \frac{18}{5} (x + 3)^{\frac{5}{3}} + \frac{27}{2} (x + 3)^{\frac{2}{3}} + C

Solution steps

Apply u-substitution

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int u^{\frac{5}{3}} d u = \frac{3}{8} u^{\frac{8}{3}}

\int 6 u^{\frac{2}{3}} d u = \frac{18}{5} u^{\frac{5}{3}}

= \frac{3}{8} u^{\frac{8}{3}} - \frac{18}{5} u^{\frac{5}{3}} + \frac{27}{2} u^{\frac{2}{3}}

Substitute back

u = x + 3

= \frac{3}{8} (x + 3)^{\frac{8}{3}} - \frac{18}{5} (x + 3)^{\frac{5}{3}} + \frac{27}{2} (x + 3)^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{8} (x + 3)^{\frac{8}{3}} - \frac{18}{5} (x + 3)^{\frac{5}{3}} + \frac{27}{2} (x + 3)^{\frac{2}{3}} + C

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\int sin (9 t) sin (4 t) d t

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What is the integral of (x^2)/(\sqrt[3]{x+3)} ?
The integral of (x^2)/(\sqrt[3]{x+3)} is 3/8 (x+3)^{8/3}-18/5 (x+3)^{5/3}+27/2 (x+3)^{2/3}+C