What is the solution for x(dy)/(dx)+(1-3x)y=e^{5x} ?

The solution for x(dy)/(dx)+(1-3x)y=e^{5x} is y=(e^{5x})/(2x)+(c_{1})/(e^{-3x)x}

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x(dy)/(dx)+(1-3x)y=e^{5x}

x \frac{d y}{d x} + (1 - 3 x) y = e^{5 x}

y = \frac{e ^{5 x}}{2 x} + \frac{c _{1}}{e ^{- 3 x} x}

Solution steps

x \frac{d y}{d x} + (1 - 3 x) y = e^{5 x}

Solve linear ODE:

y = \frac{e ^{5 x}}{2 x} + \frac{c _{1}}{e ^{- 3 x} x}

y = \frac{e ^{5 x}}{2 x} + \frac{c _{1}}{e ^{- 3 x} x}

f (x) = \frac{sin ( x )}{e ^{x}}

\int (x^{3} + 1.8 x^{2} - 2.4 x) d x

\frac{\partial}{\partial y} (2 y - x)

\int x^{2} (5 + 2 x^{3})^{8} d x

e^{x + 2 y} d x - e^{2 x - y} d y = 0

What is the solution for x(dy)/(dx)+(1-3x)y=e^{5x} ?
The solution for x(dy)/(dx)+(1-3x)y=e^{5x} is y=(e^{5x})/(2x)+(c_{1})/(e^{-3x)x}