What is the limit as n approaches infinity of {(1+2/n)^{4n}} ?

The limit as n approaches infinity of {(1+2/n)^{4n}} is e^8

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limit as n approaches infinity of {(1+2/n)^{4n}}

n \to \infty lim ({(1 + \frac{2}{n})^{4 n}})

e^{8}

Decimal Notation

2980.95798 \dots

Solution steps

n \to \infty lim ((1 + \frac{2}{n})^{4 n})

Apply exponent rules

= n \to \infty lim (e^{4 n l n (1 + \frac{2}{n})})

Apply the Limit Chain Rule:

e^{8}

= e^{8}

y = x^{2} e^{x} - 2 x e^{x} + 9 e^{x}

\frac{d y}{d x} - 2 y = - 1

y^{^{'}} = 0.2 x

\int_{1}^{e^{3}} x^{5} ln (x) d x

\frac{d}{d x} (8 x^{6})

What is the limit as n approaches infinity of {(1+2/n)^{4n}} ?
The limit as n approaches infinity of {(1+2/n)^{4n}} is e^8