What is the derivative of y=sin(x^3) ?

The derivative of y=sin(x^3) is cos(x^3)*3x^2

What is the first derivative of y=sin(x^3) ?

The first derivative of y=sin(x^3) is cos(x^3)*3x^2

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derivative of

y = sin (x^{3})

cos (x^{3}) \cdot 3 x^{2}

Solution steps

\frac{d}{d x} (sin (x^{3}))

Apply the chain rule:

cos (x^{3}) \frac{d}{d x} (x^{3})

= cos (x^{3}) \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= cos (x^{3}) \cdot 3 x^{2}

\int \frac{x ^{3} - x}{x ^{3}} d x

n = 0 \sum \infty (- 1 + \frac{1}{e})^{n}

\frac{d}{d θ} (3 sin (3 θ))

m \frac{7}{x}

f (x) = 2 + 7 x

What is the derivative of y=sin(x^3) ?
The derivative of y=sin(x^3) is cos(x^3)*3x^2
What is the first derivative of y=sin(x^3) ?
The first derivative of y=sin(x^3) is cos(x^3)*3x^2