What is the tangent of y=sin(9x)+sin^2(9x),(0,0) ?

The tangent of y=sin(9x)+sin^2(9x),(0,0) is y=9x

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tangent of y=sin(9x)+sin^2(9x),(0,0)

tangent of

y = sin (9 x) + sin^{2} (9 x), (0, 0)

y = 9 x

Solution steps

Find the slope of

y = sin (9 x) + sin^{2} (9 x) : \frac{d y}{d x} = cos (9 x) \cdot 9 + 18 sin (9 x) cos (9 x)

Compute the slope of

y = sin (9 x) + sin^{2} (9 x)

(0, 0) : m = 9

Find the line with slope m=

9

and passing through

(0, 0) : y = 9 x

y = 9 x

\frac{d y}{d x} + x^{2} sec (y) = 0, y (0) = 1

\frac{d}{d x} (3 - 8 x)

\int \frac{2 x ^{2} + x + 3}{( x + 1 ) ( x ^{2} + 1 )} d x

4^{- x^{8}}

\int 2 sin^{2} (x) d x

What is the tangent of y=sin(9x)+sin^2(9x),(0,0) ?
The tangent of y=sin(9x)+sin^2(9x),(0,0) is y=9x