What is the derivative of 5sec(2x) ?

The derivative of 5sec(2x) is 10sec(2x)tan(2x)

What is the first derivative of 5sec(2x) ?

The first derivative of 5sec(2x) is 10sec(2x)tan(2x)

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\frac{d}{d x} (5 sec (2 x))

10 sec (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (5 sec (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 5 sec (2 x) tan (2 x) \cdot 2

Simplify

= 10 sec (2 x) tan (2 x)

\int y ln (y) d y

\frac{d y}{d x}, e^{2 x} sin (3 x) - e^{- 2 x} sin (2 y) = 13 x y^{2}

cos (x) + sin (x)

\int_{0}^{k} \frac{1}{x ^{2} + 1} d x

\int \frac{e ^{2 x}}{2} d x

What is the derivative of 5sec(2x) ?
The derivative of 5sec(2x) is 10sec(2x)tan(2x)
What is the first derivative of 5sec(2x) ?
The first derivative of 5sec(2x) is 10sec(2x)tan(2x)