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Popular >

integral of 1/(t+1)

Solution

\int \frac{1}{t + 1} d t

Solution

ln ∣ t + 1 ∣ + C

Solution steps

\int \frac{1}{t + 1} d t

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = t + 1

= ln ∣ t + 1 ∣

Add a constant to the solution

= ln ∣ t + 1 ∣ + C

Popular Examples

limit as x approaches 3 of x/((3-x)^2)

x \to 3 lim (\frac{x}{( 3 - x ) ^{2}})

sum from n=1 to infinity of (ln(3n))/n

n = 1 \sum \infty \frac{ln ( 3 n )}{n}

limit as x approaches infinity of \sqrt[3]{x/(x^2+3)}

derivative of cos(bx)

\frac{d}{d x} (cos (b x))

integral of kx^2

\int k x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(t+1) ?
The integral of 1/(t+1) is ln|t+1|+C