What is the integral from 0 to 0.6 of 250x ?

The integral from 0 to 0.6 of 250x is 45

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integral from 0 to 0.6 of 250x

\int_{0}^{0.6} 250 x d x

45

Solution steps

\int_{0}^{0.6} 250 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 250 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 250 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 250 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 250 \cdot 0.18

Simplify

= 45

\int - 2 sin (2 t) d t

\frac{d}{d x} y = (- 2. 6^{\frac{1}{2}})

ln (x^{61})

\frac{d}{d x} (\frac{5 x}{x ^{2} + 5})

\int_{0}^{\frac{π}{2}} sin^{2} (2 x) d x

What is the integral from 0 to 0.6 of 250x ?
The integral from 0 to 0.6 of 250x is 45