What is the derivative of f(x)=(x^2+3)^4 ?

The derivative of f(x)=(x^2+3)^4 is 8x(x^2+3)^3

What is the first derivative of f(x)=(x^2+3)^4 ?

The first derivative of f(x)=(x^2+3)^4 is 8x(x^2+3)^3

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derivative of

f (x) = (x^{2} + 3)^{4}

8 x (x^{2} + 3)^{3}

Solution steps

\frac{d}{d x} ((x^{2} + 3)^{4})

Apply the chain rule:

4 (x^{2} + 3)^{3} \frac{d}{d x} (x^{2} + 3)

= 4 (x^{2} + 3)^{3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= 4 (x^{2} + 3)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} + 3)^{3}

\int \frac{1}{( 1 - x ) ^{3} x ^{2} - 2 x - 1} d x

\int \frac{1}{3 x - x ^{2}} d x

5 \frac{d x}{d t} + 10 x = 120 sin (60 t)

f (x) = \frac{1}{x - 2}, at x = 6

What is the derivative of f(x)=(x^2+3)^4 ?
The derivative of f(x)=(x^2+3)^4 is 8x(x^2+3)^3
What is the first derivative of f(x)=(x^2+3)^4 ?
The first derivative of f(x)=(x^2+3)^4 is 8x(x^2+3)^3