What is the sum from n=1 to infinity of 17-7/(n^3) ?

The sum from n=1 to infinity of 17-7/(n^3) is diverges

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sum from n=1 to infinity of 17-7/(n^3)

n = 1 \sum \infty 17 - \frac{7}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty 17 - \frac{7}{n ^{3}}

Simplify

17 - \frac{7}{n ^{3}} : \frac{17 n ^{3} - 7}{n ^{3}}

= n = 1 \sum \infty \frac{17 n ^{3} - 7}{n ^{3}}

Apply Series Divergence Test:

diverges

= diverges

\int sinh (x) cosh^{4} (x) d x

y = 2 x^{2}, y = 3 - x

x \to 5 lim (\frac{4 x}{x - 5})

y^{^{'}} = (t + y)^{2} - 1, y (3) = 6

What is the sum from n=1 to infinity of 17-7/(n^3) ?
The sum from n=1 to infinity of 17-7/(n^3) is diverges