What is the limit as x approaches 0 of 1/(3x^3) ?

The limit as x approaches 0 of 1/(3x^3) is diverges

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limit as x approaches 0 of 1/(3x^3)

x \to 0 lim (\frac{1}{3 x ^{3}})

diverges

Solution steps

x \to 0 lim (\frac{1}{3 x ^{3}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{3 x ^{3}}) = \infty

x \to 0 - lim (\frac{1}{3 x ^{3}}) = - \infty

= diverges

y^{^{''}} - 2 y^{^{'}} + y = t^{3} e^{t}

\frac{d}{d x} (4 x^{2} cos (3 x))

y^{^{''}} - 4 y^{^{'}} + 4 y = x e^{2 x}

\frac{d}{d x} ((1 + x + x^{2})^{99})

\frac{\partial}{\partial u} ((u^{2} + v^{2})^{\frac{3}{2}})

What is the limit as x approaches 0 of 1/(3x^3) ?
The limit as x approaches 0 of 1/(3x^3) is diverges