What is the derivative of f(x)=(2x+1)(3x-2) ?

The derivative of f(x)=(2x+1)(3x-2) is 12x-1

What is the first derivative of f(x)=(2x+1)(3x-2) ?

The first derivative of f(x)=(2x+1)(3x-2) is 12x-1

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derivative of

f (x) = (2 x + 1) (3 x - 2)

12 x - 1

Solution steps

\frac{d}{d x} ((2 x + 1) (3 x - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x + 1, g = 3 x - 2

= \frac{d}{d x} (2 x + 1) (3 x - 2) + \frac{d}{d x} (3 x - 2) (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

\frac{d}{d x} (3 x - 2) = 3

= 2 (3 x - 2) + 3 (2 x + 1)

Simplify

2 (3 x - 2) + 3 (2 x + 1) : 12 x - 1

= 12 x - 1

\int_{3}^{e^{4}} \frac{1}{x} d x

y = ln (x), y = 0, x = e

\int cos (2) (x) d x

\int (8 + u) d u

\frac{d y}{d x} + 4 y = 7

What is the derivative of f(x)=(2x+1)(3x-2) ?
The derivative of f(x)=(2x+1)(3x-2) is 12x-1
What is the first derivative of f(x)=(2x+1)(3x-2) ?
The first derivative of f(x)=(2x+1)(3x-2) is 12x-1