What is the derivative of x^4-4x^3+6 ?

The derivative of x^4-4x^3+6 is 4x^3-12x^2

What is the first derivative of x^4-4x^3+6 ?

The first derivative of x^4-4x^3+6 is 4x^3-12x^2

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\frac{d}{d x} (x^{4} - 4 x^{3} + 6)

4 x^{3} - 12 x^{2}

Solution steps

\frac{d}{d x} (x^{4} - 4 x^{3} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (6) = 0

= 4 x^{3} - 12 x^{2} + 0

Simplify

= 4 x^{3} - 12 x^{2}

x^{^{''}} - 5 x^{^{'}} + 6 x = cos (t) e^{- t}

f (x) = \frac{2}{x + 3}, at a = - 4

n = 1 \sum \infty sin (n + 1)

(10 - x) y^{2} = x^{3}, (2, 1)

\int \frac{1}{16 x ^{2} + 4} d x

What is the derivative of x^4-4x^3+6 ?
The derivative of x^4-4x^3+6 is 4x^3-12x^2
What is the first derivative of x^4-4x^3+6 ?
The first derivative of x^4-4x^3+6 is 4x^3-12x^2