What is the derivative of (x^2+3^4) ?

The derivative of (x^2+3^4) is 8x(x^2+3)^3

What is the first derivative of (x^2+3^4) ?

The first derivative of (x^2+3^4) is 8x(x^2+3)^3

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\frac{d}{d x} ((x^{2} + 3)^{4})

8 x (x^{2} + 3)^{3}

Solution steps

\frac{d}{d x} ((x^{2} + 3)^{4})

Apply the chain rule:

4 (x^{2} + 3)^{3} \frac{d}{d x} (x^{2} + 3)

= 4 (x^{2} + 3)^{3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= 4 (x^{2} + 3)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} + 3)^{3}

\frac{d}{d x} (5 e^{x})

\frac{\partial}{\partial x} ((3 x^{2} + 3 x - 1) (2 x + 3))

y = (x + 5) (3 x + 8)

\int \frac{( x + 1 )}{( x ^{2} + 2 x + 2 ) ^{3}} d x

\frac{d y}{d x} = 1 + \frac{y}{x}

What is the derivative of (x^2+3^4) ?
The derivative of (x^2+3^4) is 8x(x^2+3)^3
What is the first derivative of (x^2+3^4) ?
The first derivative of (x^2+3^4) is 8x(x^2+3)^3