What is the limit as x approaches-1 of 1/(x+1) ?

The limit as x approaches-1 of 1/(x+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of 1/(x+1)

x \to - 1 lim (\frac{1}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= diverges

x \to 0 lim (e^{7 x})

\int arccos (7 x) d x

n = 0 \sum \infty n + 2

\frac{d x}{d t} = - 2 x - 3 x^{2}

(cos^{2} (s) - 4 s^{2})^{2}

What is the limit as x approaches-1 of 1/(x+1) ?
The limit as x approaches-1 of 1/(x+1) is diverges