What is the derivative of f(x)=x^3-1 ?

The derivative of f(x)=x^3-1 is 3x^2

What is the first derivative of f(x)=x^3-1 ?

The first derivative of f(x)=x^3-1 is 3x^2

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derivative of

f (x) = x^{3} - 1

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\frac{\partial}{\partial x} (4 x^{3} - 5 x^{2} + 8 x)

y^{^{'}} = \frac{2 x + y}{2 x + y + 3}

\int sin^{2} (5 x) d x

\frac{\partial}{\partial x} (5 x^{2} + y^{2})

What is the derivative of f(x)=x^3-1 ?
The derivative of f(x)=x^3-1 is 3x^2
What is the first derivative of f(x)=x^3-1 ?
The first derivative of f(x)=x^3-1 is 3x^2