What is the integral from 7 to infinity of e^{-2x}+x^{-3} ?

The integral from 7 to infinity of e^{-2x}+x^{-3} is 1/98+1/(2e^{14)}

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integral from 7 to infinity of e^{-2x}+x^{-3}

\int_{7}^{\infty} e^{- 2 x} + x^{- 3} d x

\frac{1}{98} + \frac{1}{2 e ^{14}}

Decimal Notation

0.01020 \dots

Solution steps

\int_{7}^{\infty} e^{- 2 x} + x^{- 3} d x

Compute the indefinite integral:

\int e^{- 2 x} + x^{- 3} d x = - \frac{1}{2} e^{- 2 x} - \frac{1}{2 x ^{2}} + C

Compute the boundaries:

\int_{7}^{\infty} e^{- 2 x} + x^{- 3} d x = 0 - (- \frac{1}{2 e ^{14}} - \frac{1}{98})

= 0 - (- \frac{1}{2 e ^{14}} - \frac{1}{98})

Simplify

= \frac{1}{98} + \frac{1}{2 e ^{14}}

x^{3} + y^{3} - 9 x y = 0, (2, 4)

y^{^{'}} = y^{2} x

x \to \frac{π}{4} lim (3 cos (x))

\frac{d}{d x} (x (8 - x)^{\frac{1}{3}})

What is the integral from 7 to infinity of e^{-2x}+x^{-3} ?
The integral from 7 to infinity of e^{-2x}+x^{-3} is 1/98+1/(2e^{14)}