What is the limit as x approaches 3 of (x^3-6x^2+9)/(x^2-9) ?

The limit as x approaches 3 of (x^3-6x^2+9)/(x^2-9) is diverges

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limit as x approaches 3 of (x^3-6x^2+9)/(x^2-9)

x \to 3 lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9}) = - \infty

x \to 3 - lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9}) = \infty

= diverges

y = 7 x - 4 x^{2}, (- 3, - 57)

x \to 999 lim (x^{2} - 1)

\int \frac{4 x}{1 - 2 x} d x

\frac{s + 4}{s ^{2} + 4 s + 8}

\frac{d y}{d x} = 2 x y, y (0) = 1

What is the limit as x approaches 3 of (x^3-6x^2+9)/(x^2-9) ?
The limit as x approaches 3 of (x^3-6x^2+9)/(x^2-9) is diverges