What is (\partial)/(\partial y)(((x^2y))/(x^2+y^2)) ?

The answer to (\partial)/(\partial y)(((x^2y))/(x^2+y^2)) is (x^2(x^2-y^2))/((x^2+y^2)^2)

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(\partial)/(\partial y)(((x^2y))/(x^2+y^2))

\frac{\partial}{\partial y} (\frac{( x ^{2} y )}{x ^{2} + y ^{2}})

\frac{x ^{2} ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{( x ^{2} y )}{x ^{2} + y ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (\frac{y}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= x^{2} \frac{\frac{\partial}{\partial y} ( y ) ( x ^{2} + y ^{2} ) - \frac{\partial}{\partial y} ( x ^{2} + y ^{2} ) y}{( x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= x^{2} \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 yy}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

x^{2} \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 yy}{( x ^{2} + y ^{2} ) ^{2}} : \frac{x ^{2} ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{x ^{2} ( x ^{2} - y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

6 x^{2} + 2 x y + 2 y^{2} = 74, (3, 2)

\int \frac{1}{1 - 36 x ^{2}} d x

y^{^{'''}} - 4 y^{^{''}} - y^{^{'}} + 4 y = 0

x \to 2 lim (\frac{3 ^{x} - 9}{x - 2})

What is (\partial)/(\partial y)(((x^2y))/(x^2+y^2)) ?
The answer to (\partial)/(\partial y)(((x^2y))/(x^2+y^2)) is (x^2(x^2-y^2))/((x^2+y^2)^2)