What is the derivative of y=20x^3(x^4+5)^4 ?

The derivative of y=20x^3(x^4+5)^4 is 20(3x^2(x^4+5)^4+16x^6(x^4+5)^3)

What is the first derivative of y=20x^3(x^4+5)^4 ?

The first derivative of y=20x^3(x^4+5)^4 is 20(3x^2(x^4+5)^4+16x^6(x^4+5)^3)

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derivative of

y = 20 x^{3} (x^{4} + 5)^{4}

20 (3 x^{2} (x^{4} + 5)^{4} + 16 x^{6} (x^{4} + 5)^{3})

Solution steps

\frac{d}{d x} (20 x^{3} (x^{4} + 5)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 20 \frac{d}{d x} (x^{3} (x^{4} + 5)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = (x^{4} + 5)^{4}

= 20 (\frac{d}{d x} (x^{3}) (x^{4} + 5)^{4} + \frac{d}{d x} ((x^{4} + 5)^{4}) x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} ((x^{4} + 5)^{4}) = 16 x^{3} (x^{4} + 5)^{3}

= 20 (3 x^{2} (x^{4} + 5)^{4} + 16 x^{3} (x^{4} + 5)^{3} x^{3})

16 x^{3} (x^{4} + 5)^{3} x^{3} = 16 x^{6} (x^{4} + 5)^{3}

= 20 (3 x^{2} (x^{4} + 5)^{4} + 16 x^{6} (x^{4} + 5)^{3})

\int_{0}^{4} (x - 4)^{2} d x

\frac{\partial}{\partial x} (- sin (y))

x \to 1 - lim (ln (x))

\frac{x d y}{d x} + 2 y = 3

y^{^{''}} + 3 y^{^{'}} = 2 t^{4} + t^{2} e^{- 3 t} + sin (3 t)

What is the derivative of y=20x^3(x^4+5)^4 ?
The derivative of y=20x^3(x^4+5)^4 is 20(3x^2(x^4+5)^4+16x^6(x^4+5)^3)
What is the first derivative of y=20x^3(x^4+5)^4 ?
The first derivative of y=20x^3(x^4+5)^4 is 20(3x^2(x^4+5)^4+16x^6(x^4+5)^3)