What is the derivative of x*e^x-1 ?

The derivative of x*e^x-1 is e^xx+e^x

What is the first derivative of x*e^x-1 ?

The first derivative of x*e^x-1 is e^xx+e^x

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\frac{d}{d x} (x \cdot e^{x} - 1)

e^{x} x + e^{x}

Solution steps

\frac{d}{d x} (x e^{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x e^{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

\frac{d}{d x} (1) = 0

= e^{x} + e^{x} x - 0

Simplify

= e^{x} x + e^{x}

\frac{\partial}{\partial x} (4 e^{x^{7} y})

\int x^{2} - 4 x + 29 d x

\frac{d}{d x} ((1 + x)^{2} ln (1 + x))

y^{10} y^{^{'}} = 13 cos (π x)

\int 7 - 3 (1 + x^{2})^{- 1} d x

What is the derivative of x*e^x-1 ?
The derivative of x*e^x-1 is e^xx+e^x
What is the first derivative of x*e^x-1 ?
The first derivative of x*e^x-1 is e^xx+e^x