What is the limit as x approaches 2 of x^2-4x+1 ?

The limit as x approaches 2 of x^2-4x+1 is -3

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limit as x approaches 2 of x^2-4x+1

x \to 2 lim (x^{2} - 4 x + 1)

- 3

Solution steps

x \to 2 lim (x^{2} - 4 x + 1)

Plug in the value

x = 2

= 2^{2} - 4 \cdot 2 + 1

Simplify

= - 3

\int \frac{1}{( 1 + x ^{4} )} d x

\int \frac{x ^{4}}{( 7 + x ^{5} ) ^{2}} d x

n = 2 \sum \infty \frac{3 ^{n}}{1 2 ^{n}}

4 y^{^{''}} - 4 y^{^{'}} + y = 8 e^{\frac{x}{2}}

y = 8 e^{17 t}

What is the limit as x approaches 2 of x^2-4x+1 ?
The limit as x approaches 2 of x^2-4x+1 is -3