What is the integral of 1/(2xln(x)) ?

The integral of 1/(2xln(x)) is 1/2 ln|ln(x)|+C

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integral of 1/(2xln(x))

\int \frac{1}{2 x ln ( x )} d x

\frac{1}{2} ln ∣ ln (x) ∣ + C

Solution steps

\int \frac{1}{2 x ln ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x ln ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = ln (x)

= \frac{1}{2} ln ∣ ln (x) ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ ln (x) ∣ + C

\frac{d}{d x} (\frac{7 x}{x ^{2} + 49})

\frac{d ^{4}}{d x ^{4}} (4 e^{x^{2}})

\int \frac{3}{x ^{2} ( x - 1 )} d x

\frac{\partial}{\partial x} (y^{2} ln (x))

What is the integral of 1/(2xln(x)) ?
The integral of 1/(2xln(x)) is 1/2 ln|ln(x)|+C